Exercise · ZW-MODULAR-INVERSE-008 · ★★☆ Intermediate
Solve \(3x\equiv 2\pmod{7}\) using the inverse of \(3\).
Choose one option.
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- A. \(3\)
Exercise · ZW-MODULAR-INVERSE-008 · ★★☆ Intermediate
Choose one option.
The inverse of \(3\) modulo \(7\) is \(5\), so \(x\equiv 5\cdot 2\equiv 3\pmod{7}\). Four does not satisfy the congruence.
The modular inverse of an integer \(a\) modulo \(m\) is an integer \(b\) whose product with \(a\) is congruent to 1 modulo \(m\).