Exercise · ZW-MULTIVARIABLE-CHAIN-RULE-006 · ★★☆ Intermediate

Let \(z=x^2+xy\) with \(x=s+t\), \(y=st\). Compute \(\dfrac{\partial z}{\partial s}\) at \((s,t)=(1,2)\).

Choose one option.

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  • C. \(14\)

Explanation

At \((1,2)\): \(x=3\), \(y=2\). \(z_s=(2x+y)\cdot1+x\cdot t=8+6=14\).

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Review the concept: Chain rule in several variables

The chain rule for \(z=f(x,y)\), with \(x=x(t)\) and \(y=y(t)\), gives the derivative of the composition as the sum of what each intermediate variable contributes: its partial of \(f\) times its own derivative.

\[\frac{dz}{dt}=\frac{\partial f}{\partial x}\frac{dx}{dt}+\frac{\partial f}{\partial y}\frac{dy}{dt}\]

More practice problems: chain rule in several variables

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