Exercise · ZW-NEWTON-S-METHOD-FOR-OPTIMIZATION-010 · ★★☆ Intermediate
For \(f(x,y)=x^3-3x+y^2\), what happens if the Newton step is applied from \((0,1)\)? Use the Hessian \(\mathrm{diag}(6x,2)\).
Choose one option.
A The step is \((0,0)\) because the gradient vanishes B The Hessian is singular at \((0,1)\), so the step is undefined C The step leads to \((1,0)\), which is a local minimum D The step leads to \((-1,0)\), which is a local maximum
Show answer B. The Hessian is singular at \((0,1)\), so the step is undefined
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Explanation At \((0,1)\) the Hessian \(\mathrm{diag}(0,2)\) is singular because \(6x=0\), so it cannot be inverted. The other options assume an invertible Hessian or a vanishing gradient that do not hold.
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