Exercise · ZW-OPEN-SET-IN-A-METRIC-SPACE-003 · ★☆☆ Basic

Why is \((0,1]\) not open in usual \(\mathbb{R}\)?

Choose one option.

Show answer
  • B. Because no ball centered at \(1\) is contained in it

Explanation

Every ball \(B(1,r)\) contains \(1+r/2>1\), which is not in the set. Missing \(0\) or being bounded does not prevent openness: \((0,1)\) is open and bounded.

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Review the concept: Open set in a metric space

A subset \(U\) of a metric space \((X,d)\) is open if every point \(x\in U\) is the center of some open ball \(B(x,r)\) contained in \(U\).

\[\forall x\in U\ \ \exists r>0:\ B(x,r)\subseteq U\]

More practice problems: open set in a metric space

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