Exercise · ZW-OPEN-SET-IN-A-METRIC-SPACE-003 · ★☆☆ Basic
Why is \((0,1]\) not open in usual \(\mathbb{R}\)?
Choose one option.
Show answer
- B. Because no ball centered at \(1\) is contained in it
Exercise · ZW-OPEN-SET-IN-A-METRIC-SPACE-003 · ★☆☆ Basic
Choose one option.
Every ball \(B(1,r)\) contains \(1+r/2>1\), which is not in the set. Missing \(0\) or being bounded does not prevent openness: \((0,1)\) is open and bounded.
A subset \(U\) of a metric space \((X,d)\) is open if every point \(x\in U\) is the center of some open ball \(B(x,r)\) contained in \(U\).
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