Exercise · ZW-PARTIAL-ORDER-RELATION-008 · ★★☆ Intermediate

\(R=\{(1,1),(2,2),(3,3),(1,2),(2,3)\}\) on \(\{1,2,3\}\) is not a partial order. Which pair suffices to add to make it one?

Choose one option.

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  • A. \((1,3)\)

Explanation

Transitivity fails: \(1R2\) and \(2R3\) require \(1R3\). Adding \((3,1)\), \((2,1)\) or \((3,2)\) breaks antisymmetry.

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Review the concept: Partial order relation

A relation \(\preceq\) on a set \(S\) that is reflexive, antisymmetric and transitive, and therefore orders some pairs of elements of \(S\).

\[a\preceq a;\quad (a\preceq b\ \wedge\ b\preceq a)\Rightarrow a=b;\quad (a\preceq b\ \wedge\ b\preceq c)\Rightarrow a\preceq c\]

More practice problems: partial order relation

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