Exercise · ZW-PATH-CONNECTED-SPACE-003 · ★☆☆ Basic

Is the space \(X=\{1,2,3\}\) with the indiscrete topology path-connected?

Choose one option.

Show answer
  • B. Yes, because every function \([0,1]\to X\) is continuous

Explanation

In the indiscrete topology the only open sets are \(\varnothing\) and \(X\), with preimages \(\varnothing\) and \([0,1]\). So every function is continuous and two points are joined by a two-valued path.

Study General topology in ZWMath →

Review the concept: Path-connected space

A space \(X\) is path-connected if every pair of points \(a,b\in X\) is joined by a path: a continuous function \(\gamma:[0,1]\to X\) with \(\gamma(0)=a\) and \(\gamma(1)=b\).

\[\forall a,b\in X\ \exists\,\gamma:[0,1]\to X\text{ continuous},\ \gamma(0)=a,\ \gamma(1)=b\]

More practice problems: path-connected space

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