Exercise · ZW-QUADRIC-SURFACE-006 · ★★☆ Intermediate
What is the trace of \(z^2=x^2+y^2\) in the plane \(z=0\)?
Choose one option.
Show answer
- C. A single point, the origin
Explanation
With \(z=0\) we get \(x^2+y^2=0\), whose only real solution is \((0,0)\): the vertex of the cone.
Review the concept: Quadric surface
A quadric surface is the set of points \((x,y,z)\) in space that satisfy a second-degree equation in \(x\), \(y\), \(z\) with real coefficients \(A,B,C,D,E,F,G,H,I,J\).
\[Ax^2+By^2+Cz^2+Dxy+Exz+Fyz+Gx+Hy+Iz+J=0\]
More practice problems: quadric surface
- ZW-QUADRIC-SURFACE-001 Find the radius of the surface x^2+y^2+z^2=9.
- ZW-QUADRIC-SURFACE-002 Which quadric is (x^2)/(4)+(y^2)/(9)+z^2=1?
- ZW-QUADRIC-SURFACE-003 What curve results from cutting z=x^2+y^2 with the plane z=4?
- ZW-QUADRIC-SURFACE-004 Classify x^2+y^2-z^2=1.
- ZW-QUADRIC-SURFACE-005 What is the intersection of x^2+y^2-z^2=-1 with the plane z=0?
- ZW-QUADRIC-SURFACE-007 For z=x^2-y^2, what is the trace in the plane x=0?
- ZW-QUADRIC-SURFACE-008 Complete the square in x^2+y^2+z^2-2x+4y=4 and give the center and radius.
- ZW-QUADRIC-SURFACE-009 Which of these points lies on the surface x^2+y^2=4 in space?