Exercise · ZW-STIRLING-NUMBER-OF-THE-FIRST-KIND-007 · ★★☆ Intermediate
With \(c(4,2)=11\) and \(c(4,1)=6\), use \(c(n,k)=(n-1)c(n-1,k)+c(n-1,k-1)\) to find \(c(5,2)\).
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Explanation
With \(n=5\) and \(k=2\): \(4\cdot 11+6=50\). Swapping the coefficients gives 35, and dropping the second term gives 44.
The Stirling number of the first kind \(c(n,k)\) counts the permutations of \(n\) elements that have exactly \(k\) cycles.
\[x(x+1)\cdots(x+n-1)=\sum_{k=0}^{n} c(n,k)\,x^{k}\]
More practice problems: stirling number of the first kind
- ZW-STIRLING-NUMBER-OF-THE-FIRST-KIND-001 What does the number c(n,k) count?
- ZW-STIRLING-NUMBER-OF-THE-FIRST-KIND-002 The permutations of \1,2,3\ with a single cycle are the 3-cycles. What is c(3,1)?
- ZW-STIRLING-NUMBER-OF-THE-FIRST-KIND-003 What is c(n,n) for every n≥ 1?
- ZW-STIRLING-NUMBER-OF-THE-FIRST-KIND-004 What is c(n,0) for n≥ 1?
- ZW-STIRLING-NUMBER-OF-THE-FIRST-KIND-005 What is c(n,1)?
- ZW-STIRLING-NUMBER-OF-THE-FIRST-KIND-006 Use c(4,1)=6, c(4,2)=11, c(4,3)=6 and c(4,4)=1. What is the sum of the row n=4?
- ZW-STIRLING-NUMBER-OF-THE-FIRST-KIND-008 Expand x(x+1)(x+2)=∑_k c(3,k) x^k. What is c(3,2)?
- ZW-STIRLING-NUMBER-OF-THE-FIRST-KIND-009 Using the row n=4, where c(4,1)=6, c(4,2)=11, c(4,3)=6 and c(4,4)=1, compute ∑_k=1^4 k c(4,k).