Exercise · ZW-SYSTEM-OF-LINEAR-EQUATIONS-007 · ★★☆ Intermediate

Solve the system \(x+y+z=6,\; x-y+z=2,\; 2x+y-z=1\).

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  • C. \((x,y,z)=(1,2,3)\)

Explanation

Subtracting the second equation from the first: \(2y=4\), so \(y=2\). Then \(x+z=4\) and \(2x-z=-1\); adding, \(3x=3\), \(x=1\) and \(z=3\).

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Review the concept: System of linear equations

A system of linear equations is a set of linear equations in the same unknowns. A solution is an assignment of values that satisfies all the equations at once.

\[\begin{aligned}a_{11}x_1+\cdots+a_{1n}x_n&=b_1\\ \vdots\qquad&\\ a_{m1}x_1+\cdots+a_{mn}x_n&=b_m\end{aligned}\]

More practice problems: system of linear equations

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