Exercise · ZW-VARIATION-OF-PARAMETERS-007 · ★★☆ Intermediate

With \(y_1=e^{t}\), \(y_2=e^{-t}\) and \(W=-2\), find \(y_p\) for \(y''-y=e^{2t}\) by variation of parameters.

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  • D. \(\tfrac13e^{2t}\)

Explanation

\(u_1=\int\!\frac{-y_2g}{W}=\tfrac12e^{t}\) and \(u_2=\int\!\frac{y_1g}{W}=-\tfrac16e^{3t}\). Then \(y_p=\tfrac12e^{2t}-\tfrac16e^{2t}=\tfrac13e^{2t}\).

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Review the concept: Variation of parameters

A method that builds a particular solution \(y_p\) of \(y''+py'+qy=g(t)\) from two homogeneous solutions \(y_1,y_2\) and their Wronskian \(W\), by letting the constants vary.

\[y_p=-y_1\!\int\!\frac{y_2\,g}{W}\,dt+y_2\!\int\!\frac{y_1\,g}{W}\,dt\]

More practice problems: variation of parameters

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