Exercise · ZW-VECTOR-SPACE-006 · ★★☆ Intermediate
Let \(S=\{f:\mathbb{R}\to\mathbb{R}\mid f(0)=1\}\). If \(f,g\in S\), what is \((f+g)(0)\) and what does it imply?
Choose one option.
A It equals \(1\); \(S\) is closed under addition B It equals \(2\); \(S\) is not closed under addition C It equals \(0\); \(S\) contains the zero vector D It equals \(2\); \(S\) is closed under addition
Show answer B. It equals \(2\); \(S\) is not closed under addition
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Explanation \((f+g)(0)=f(0)+g(0)=1+1=2\ne 1\), so \(f+g\notin S\) and \(S\) is not a vector space .
A real vector space is a set \(V\) with an addition and a scalar multiplication by reals satisfying eight axioms; its elements are called vectors, whether arrows, matrices or functions .
\[u+v\in V,\quad cv\in V,\quad (c+d)v=cv+dv\]
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