Exercise · ZW-VITALI-SET-006 · ★★☆ Intermediate
If \(V\) is a Vitali set and \(q\in\mathbb{Q}\), what is the Lebesgue measure of \(V+q\) when \(m(V)=0\)?
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Explanation
Measure is translation invariant, so \(V+q\) has the same zero measure as \(V\). The other answers ignore translation invariance.
Review the concept: Vitali set
The Vitali set is a subset of \([0,1]\) containing exactly one representative of each class of \(\mathbb{R}\) modulo \(\mathbb{Q}\), and it is not Lebesgue measurable.
\[x \sim y \iff x - y \in \mathbb{Q}\]
More practice problems: vitali set
- ZW-VITALI-SET-001 Which axiom is used to choose a representative from each equivalence class in Vitali's construction?
- ZW-VITALI-SET-002 What equivalence relation is used to construct the Vitali set?
- ZW-VITALI-SET-003 Which property of Lebesgue measure is used in Vitali's contradiction?
- ZW-VITALI-SET-004 What is the Lebesgue measure of the interval [0,1]?
- ZW-VITALI-SET-005 How many rationals in [-1,1] are used to translate the Vitali set?
- ZW-VITALI-SET-007 If V is a Vitali set, what does the union bigcup_n (V+q_n) contain for an enumeration q_n of ℚ∩[-1,…
- ZW-VITALI-SET-008 If m(V)>0 and the translates V+q_n are disjoint, what follows about the measure of their union?
- ZW-VITALI-SET-009 What is the error in claiming the Cantor set is non-measurable because it is uncountable?