Ordinals and axioms · Definition
Transfinite induction
When indices stop being natural numbers, ordinary induction no longer covers the whole process. This method proves properties and supports definitions along any well-ordering, especially on the ordinals.
Definition
Principle that proves a property holds for all ordinal numbers \(\mathrm{On}\) by showing that if it holds for all ordinals below a given \(\alpha\), it also holds for \(\alpha\).
The general version does not separate cases: it is enough to show that \(P(\alpha)\) follows from \(P(\beta)\) for every \(\beta<\alpha\). Its validity comes from the well-ordering of the ordinals, since a counterexample would have a least element, and that least element would yield a contradiction.
To prove that \(0+\alpha=\alpha\) for every ordinal, the proof can be organized into three cases: \(0+0=0\); at a successor, \(0+(\beta+1)=(0+\beta)+1=\beta+1\) by hypothesis; and at a limit, \(0+\lambda=\sup_{\beta<\lambda}(0+\beta)=\sup_{\beta<\lambda}\beta=\lambda\).
The most common mistake is treating a limit as a successor, looking for an immediate predecessor \(\lambda-1\) that does not exist. It is also not enough to check only the immediately preceding ordinal, because the general step needs every \(\beta<\alpha\).
Think about it
Why does \(P(0)\) follow without a separate proof?
Because there is no \(\beta<0\), so the condition is vacuous.
Exercises 10
- What does the general step of transfinite induction require?
- If \(P(\alpha)\) follows whenever \(P(\beta)\) holds for all \(\beta<\alpha\), what do we conclude?
- How is the successor case \(\alpha=\beta+1\) handled in the general version?
- Which of these ordinals is a limit ordinal?
- On which kind of ordered sets can transfinite induction be applied?
- Let \(P(\alpha): \alpha\notin\alpha\). The general step assumes \(\alpha\in\alpha\). What follows?
- If \(0+\alpha=\alpha\) for every ordinal \(\alpha\), what is \(0+(\omega+1)\)?
- If \(0+\beta=\beta\) for all \(\beta<\lambda\) and \(\lambda\) is a limit ordinal, what is \(0+\lambda\)?
- Is it valid to conclude that \(P\) holds for every ordinal if \(P(0)\) holds and \(P(\beta)\) implies \(P(\beta+1)\) for every \(\beta\)? Give a counterexample if not.
- Let \(P(\alpha): 1+\alpha=\alpha\). Evaluate \(P(0)\), \(P(1)\) and \(P(\omega)\). What can be concluded?
References
- Herbert B. Enderton, Elements of Set Theory, 1st edition, Academic Press, 1977.
- Thomas Jech, Set Theory (The Third Millennium Edition), 3rd millennium edition, Springer, 2003.