Ordinals and axioms · Definition
Well-ordering
Before you start you need to know
The natural numbers can be traversed from the first one onward without ever going backward. Well-ordering formalizes that intuition and extends it to any set.
Definition
A set \(A\) is well-ordered by \(<\) if \(<\) is a total order on \(A\) and every nonempty subset of \(A\) has a least element.
Every well-ordered set is also totally ordered, so any two elements are comparable. The key property is that every nonempty subset has a least element, which rules out any infinite strictly decreasing sequence. That is why \(\mathbb{N}\) with its usual order is well-ordered, while \(\mathbb{Z}\) is not.
Take \(A=\{\frac{1}{n} : n\in\mathbb{N},\ n\ge 1\}\) with the usual order of \(\mathbb{R}\). The set \(A\) has no least element, because for each \(\frac{1}{n}\) there is a smaller \(\frac{1}{n+1}\). With the reverse order \(\ge\), however, its first element is \(1\), and the set is well-ordered.
A common mistake is to think every total order is a well-order. The interval \((0,1)\) with its usual order is totally ordered, but it has no least element, so it is not well-ordered. Having a largest element is not enough either: the set \(\{\dots,-2,-1,0\}\) has maximum \(0\) but no least element.
Think about it
Why is \(\mathbb{N}\) well-ordered but \(\mathbb{Z}\) is not?
Because every nonempty subset of \(\mathbb{N}\) has a least element, while the negative integers in \(\mathbb{Z}\) do not.
Exercises 10
- Which of the following statements describes a well-ordered set?
- Is \(\mathbb{Z}\) well-ordered by its usual order?
- Which of these sets is well-ordered by the usual order of \(\mathbb{R}\)?
- If \(A\) is well-ordered and \(B\subseteq A\) is nonempty, what holds?
- Let \(A=\{2,5,7\}\) with the usual order. What is its least element, and why is \(A\) well-ordered?
- Is the set \(\{x\in\mathbb{Q} : x>0\}\) well-ordered by its usual order?
- Let \(B=\{n\in\mathbb{N} : n^2>20\}\) with the usual order. What is its least element?
- Which of these subsets of \(\mathbb{Z}\) has a least element?
- Let \(A\) be a well-ordered set and \(f:A\to A\) such that \(f(a)<a\) for all \(a\in A\). What follows?
- Is \(\mathbb{N}\) well-ordered by the reverse order \(\ge\)? Choose the correct statement.
References
- Herbert B. Enderton, Elements of Set Theory, 1st edition, Academic Press, 1977.
- Thomas Jech, Set Theory (The Third Millennium Edition), 3rd millennium edition, Springer, 2003.