Exercise · ZW-AREA-BETWEEN-CURVES-002 · ★★☆ Intermediate
Find the area between \(y=2 x\) and \(y=x^{2}\) on \([0,2]\).
Choose one option.
Show answer
- A. \(\frac{4}{3}\)
Explanation
Between the curves, \(2 x\ge x^{2}\) on \([0,2]\), so the area is \(\displaystyle\int_{0}^{2}\left(2 x-(x^{2})\right)dx=\frac{4}{3}\).
Review the concept: Area between curves
The area between the graphs of \(f\) and \(g\) on \([a,b]\), with \(f\ge g\), is the integral of the difference \(f-g\). If the curves cross, the interval is split at the crossing points.
\[A=\int_a^b\,[f(x)-g(x)]\,dx\]
More practice problems: area between curves
- ZW-AREA-BETWEEN-CURVES-001 Find the area between y=x and y=x^2 on [0,1].
- ZW-AREA-BETWEEN-CURVES-003 Find the area between y=√x and y=x^2 on [0,1].
- ZW-AREA-BETWEEN-CURVES-004 Find the area between y=x + 2 and y=x^2 on [-1,2].
- ZW-AREA-BETWEEN-CURVES-005 Find the area between y=x^3 and y=0 on [0,1].
- ZW-AREA-BETWEEN-CURVES-006 If f≥ g on [a,b], which integral gives the area between f and g on that interval?
- ZW-AREA-BETWEEN-CURVES-007 Find the area between y=sin x and y=0 on [0,π].
- ZW-AREA-BETWEEN-CURVES-008 Find the area between y=x and y=x^3 on [0,1].
- ZW-AREA-BETWEEN-CURVES-009 Find the area between y=x^2 and y=0 on [1,2].