Derivatives · Definition
Quotient rule
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Before you start you need to know
The quotient rule differentiates a fraction of two functions without simplifying it first.
Definition
The derivative of a quotient \(\frac{f}{g}\), with \(g\ne0\), is \(\frac{f^{\prime}g-fg^{\prime}}{g^2}\).
\[\left(\frac{f}{g}\right)'=\frac{f'g-f\,g'}{g^{2}}\]
For a quotient, \(\left(\frac{f}{g}\right)'=\frac{f'g-fg'}{g^2}\). The order in the numerator matters: first the derivative of the top times the bottom, then subtract.
Guide example: with \(u=x^{2}+1\) and \(v=x-1\), \(\left(\frac{u}{v}\right)'=\frac{2x(x-1)-(x^{2}+1)}{(x-1)^{2}}=\frac{x^{2}-2x-1}{(x-1)^{2}}\).
Typical error: writing \(f'g+fg'\) in the numerator or dividing by \(g\) instead of \(g^{2}\). The minus sign and the order matter, so check both.
Think about it
Differentiate \(\frac{x}{x+1}\).
\(\frac{(x+1)-x}{(x+1)^2}=\frac{1}{(x+1)^2}\).
Exercises 10
Differentiate the following functions
- \(\displaystyle f(x)=\frac{x}{x + 1}\)
- \(\displaystyle f(x)=\frac{\sin {x}}{x}\)
- \(\displaystyle f(x)=\frac{x^{2} + 1}{x - 1}\)
- \(\displaystyle f(x)=\frac{e^{x}}{x}\)
- \(\displaystyle f(x)=\frac{x^{2}}{x^{2} + 1}\)
Problems
- In the quotient rule \(\left(\dfrac{f}{g}\right)'\), what is the correct numerator?
- According to the quotient rule, what appears in the denominator of \(\left(\frac{f}{g}\right)'\)?
- Compute \(f'(1)\) if \(f(x)=\frac{x^{3}}{x+2}\).
- Which differentiation rule is used to differentiate a quotient \(\frac{f}{g}\) of two functions?
- Compute \(f'(1)\) if \(f(x)=\frac{2x+1}{x^{2}}\).
What comes next
References
- James Stewart, Calculus: Early Transcendentals, 8.ª edición, Cengage Learning, 2015.