Exercise · ZW-AREA-BETWEEN-CURVES-003 · ★★☆ Intermediate

Find the area between \(y=\sqrt{x}\) and \(y=x^{2}\) on \([0,1]\).

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  • D. \(\frac{1}{3}\)

Explanation

Between the curves, \(\sqrt{x}\ge x^{2}\) on \([0,1]\), so the area is \(\displaystyle\int_{0}^{1}\left(\sqrt{x}-(x^{2})\right)dx=\frac{1}{3}\).

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Review the concept: Area between curves

The area between the graphs of \(f\) and \(g\) on \([a,b]\), with \(f\ge g\), is the integral of the difference \(f-g\). If the curves cross, the interval is split at the crossing points.

\[A=\int_a^b\,[f(x)-g(x)]\,dx\]

More practice problems: area between curves

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