Applications of derivatives · Definition

Optimization problems

calculusapplications

Before you start you need to know

Here a quantity is modeled as a function of one variable and its extreme values are sought on an allowed interval.

Definition

An optimization problem seeks the largest or smallest value of a quantity subject to constraints, expressed as a function of one variable.

\[\text{maximize }A(x)\ \Rightarrow\ A'(x)=0\]

Optimizing means finding the best possible value of something (maximum area, minimum cost) under a constraint. The real work is modeling: choosing variables and writing the quantity to optimize as a function of a single variable.

Then you apply what you already know: differentiate, find critical points and compare with the endpoints of the allowed interval. Always check the answer makes sense (positive lengths, domain).

If a continuous function is defined on a closed bounded interval, the extreme value theorem ensures it attains a maximum and a minimum.

Think about it

With 40 m of fence, which rectangle has maximum area?

The 10 m by 10 m square: A = x(20−x) is maximized at x = 10.

Exercises 10

References

  • James Stewart, Calculus: Early Transcendentals, 8.ª edición, Cengage Learning, 2015.