Exercise · ZW-CAUCHY-INTEGRAL-FORMULA-004 · ★☆☆ Basic

If \(f\) is holomorphic on the closed disk \(|z|\le 1\) and \(\oint_{|z|=1}\frac{f(z)}{z}\,dz=4\pi i\), what is \(f(0)\)?

Choose one option.

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  • B. \(2\)

Explanation

The formula gives \(\oint\frac{f(z)}{z}dz=2\pi i\,f(0)\). So \(2\pi i\,f(0)=4\pi i\) and \(f(0)=2\).

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Review the concept: Cauchy integral formula

The Cauchy integral formula gives the value of a holomorphic function \(f\) at a point \(z_0\) inside a simple closed contour \(C\) by means of an integral of \(f\) over \(C\).

\[f(z_0)=\frac{1}{2\pi i}\oint_C\frac{f(z)}{z-z_0}\,dz\]

More practice problems: cauchy integral formula

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