Exercise · ZW-CHANGE-OF-BASIS-010 · ★★★ Advanced
Let \(T(x)=Ax\) with \(A=\begin{pmatrix}3&1\\0&2\end{pmatrix}\) and \(B=\{(1,0),(1,-1)\}\). What is \([T]_B\)?
Choose one option.
A \(\begin{pmatrix}3&0\\0&2\end{pmatrix}\) B \(\begin{pmatrix}3&0\\1&2\end{pmatrix}\) C \(\begin{pmatrix}3&1\\0&2\end{pmatrix}\) D \(\begin{pmatrix}2&0\\0&3\end{pmatrix}\)
Show answer A. \(\begin{pmatrix}3&0\\0&2\end{pmatrix}\)
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Explanation \(T(1,0)=(3,0)=3\,b_1\) and \(T(1,-1)=(2,-2)=2\,b_2\). Each vector of \(B\) is merely scaled, so \([T]_B\) is diagonal with \(3\) and \(2\), in the order of the basis.
The change of basis \(P\) is the passage from a vector's coordinates with respect to a basis \(B\) to its coordinates with respect to another basis \(B'\) of the same space.
\[[x]_{B'}=P_{B'\leftarrow B}\,[x]_B\]
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