Exercise · ZW-CHARACTERISTIC-POLYNOMIAL-001 · ★☆☆ Basic

Compute \(p_A(\lambda)=\det(A-\lambda I)\) for \(A=\begin{pmatrix}2&1\\1&2\end{pmatrix}\).

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  • B. \(\lambda^2-4\lambda+3\)

Explanation

\(\det\begin{pmatrix}2-\lambda&1\\1&2-\lambda\end{pmatrix}=(2-\lambda)^2-1=\lambda^2-4\lambda+3\).

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Review the concept: Characteristic polynomial

The characteristic polynomial \(p_A\) of a square matrix \(A\) is the determinant of the matrix minus a multiple \(\lambda I\) of the identity \(I\), viewed as a polynomial in the variable \(\lambda\).

\[p_A(\lambda)=\det(A-\lambda I)\]

More practice problems: characteristic polynomial

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