Exercise · ZW-CHARACTERISTIC-POLYNOMIAL-003 · ★☆☆ Basic

The matrix \(A=\begin{pmatrix}1&1\\-2&4\end{pmatrix}\) has characteristic polynomial \(\lambda^2-5\lambda+6\). What are its eigenvalues?

Choose one option.

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  • C. \(2\) and \(3\)

Explanation

The eigenvalues are the roots: \(\lambda^2-5\lambda+6=(\lambda-2)(\lambda-3)=0\), that is, 2 and 3.

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Review the concept: Characteristic polynomial

The characteristic polynomial \(p_A\) of a square matrix \(A\) is the determinant of the matrix minus a multiple \(\lambda I\) of the identity \(I\), viewed as a polynomial in the variable \(\lambda\).

\[p_A(\lambda)=\det(A-\lambda I)\]

More practice problems: characteristic polynomial

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