Exercise · ZW-COMPACT-SETS-IN-HAUSDORFF-SPACES-002 · ★☆☆ Basic

Which of these subsets of \(\mathbb{R}\) cannot be compact?

Choose one option.

Show answer
  • D. \((0,1)\)

Explanation

\(\mathbb{R}\) is Hausdorff, so a compact set would be closed; \((0,1)\) is not, since its complement \((-\infty,0]\cup[1,\infty)\) is not open.

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Review the concept: Compact sets in Hausdorff spaces

Every compact subset \(K\) of a Hausdorff space \(X\) is closed in \(X\), and every closed subset of a compact space is compact.

\[K\subseteq X\ \text{compact},\ X\ \text{Hausdorff}\ \Rightarrow\ \overline{K}=K\]

More practice problems: compact sets in hausdorff spaces

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