Exercise · ZW-COMPACT-SETS-IN-HAUSDORFF-SPACES-003 · ★☆☆ Basic

In \(X=\{a,b,c\}\) with open sets \(\varnothing,\{a\},X\), the set \(\{a\}\) is:

Choose one option.

Show answer
  • A. compact and not closed

Explanation

It is finite, hence compact; its complement \(\{b,c\}\) is not open, so it is not closed. This does not contradict the theorem because the space is not Hausdorff.

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Review the concept: Compact sets in Hausdorff spaces

Every compact subset \(K\) of a Hausdorff space \(X\) is closed in \(X\), and every closed subset of a compact space is compact.

\[K\subseteq X\ \text{compact},\ X\ \text{Hausdorff}\ \Rightarrow\ \overline{K}=K\]

More practice problems: compact sets in hausdorff spaces

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