Exercise · ZW-COMPOSITION-AND-INVERSE-005 · ★☆☆ Basic

Which identity does the inverse \(f^{-1}\) of a bijection \(f\colon A\to B\) satisfy?

Choose one option.

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  • B. \(f^{-1}\circ f=\mathrm{id}_A\)

Explanation

For \(x\in A\), \(f^{-1}(f(x))=x\), which is exactly \(f^{-1}\circ f=\mathrm{id}_A\).

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Review the concept: Composition and inverse

The composition \(g\circ f\) applies \(f\) first and then \(g\). The inverse \(f^{-1}\) exists when \(f\) is bijective and undoes its action.

\[(g\circ f)(x)=g(f(x)), \quad (g\circ f)^{-1}=f^{-1}\circ g^{-1}\]

More practice problems: composition and inverse

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