Exercise · ZW-CONVERGENCE-IN-A-METRIC-SPACE-002 · ★☆☆ Basic
For \(x_n=1/n\) and \(\varepsilon=0.01\) in \(\mathbb{R}\), what is the smallest \(N\) with \(d(x_n,0)<\varepsilon\) for all \(n\ge N\)?
Choose one option.
A \(100\) B \(101\) C \(10\) D \(99\)
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Explanation We need \(1/n<0.01\), that is \(n>100\). For \(n=100\) it equals \(0.01\), which is not smaller, so \(N=101\).
A sequence \((x_n)\) in a metric space \((X,d)\) converges to \(x\in X\) if, for every \(\varepsilon>0\), there is an index \(N\) from which \(x_n\) lies within distance \(\varepsilon\) of \(x\).
\[\forall\varepsilon>0\ \ \exists N:\ n\ge N\Rightarrow d(x_n,x)<\varepsilon\]
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