Exercise · ZW-CONVERGENCE-IN-A-METRIC-SPACE-005 · ★★☆ Intermediate

In usual \(\mathbb{R}\), what happens with \(x_n=(-1)^n\)?

Choose one option.

Show answer
  • C. It does not converge

Explanation

Consecutive terms are \(2\) apart. If it converged to \(L\), with \(\varepsilon=1\) all terms from some \(N\) on would be within \(1\) of \(L\), hence less than \(2\) apart: a contradiction.

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Review the concept: Convergence in a metric space

A sequence \((x_n)\) in a metric space \((X,d)\) converges to \(x\in X\) if, for every \(\varepsilon>0\), there is an index \(N\) from which \(x_n\) lies within distance \(\varepsilon\) of \(x\).

\[\forall\varepsilon>0\ \ \exists N:\ n\ge N\Rightarrow d(x_n,x)<\varepsilon\]

More practice problems: convergence in a metric space

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