Exercise · ZW-CONVERGENCE-WITH-LIPSCHITZ-GRADIENT-002 · ★☆☆ Basic

If \( \nabla f \) is Lipschitz with constant \( L \), which gradient step is the standard choice?

Choose one option.

Show answer
  • D. \( t=1/L \)

Explanation

The step \( 1/L \) is the one used in the proof of the \( O(1/k) \) rate. Taking \( t=L \) gives a step that is too large and does not guarantee descent.

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Review the concept: Convergence with Lipschitz gradient

Result guaranteeing that gradient descent with a suitable step size converges for differentiable functions whose gradient \( \nabla f \) is Lipschitz continuous with constant \( L \).

\[f(x_k)-f^* \le \frac{L\|x_0-x^*\|^2}{2k}\]

More practice problems: convergence with lipschitz gradient

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