Exercise · ZW-CONVERGENCE-WITH-LIPSCHITZ-GRADIENT-006 · ★★☆ Intermediate

A function has \( L=4 \). What step \( t \) is safe under the rule \( t=1/L \)?

Choose one option.

Show answer
  • D. \( t=1/4 \)

Explanation

Applying \( t=1/L \) with \( L=4 \) gives \( t=1/4 \). Taking \( t=4 \) inverts the rule and yields a step that is too large.

Study Continuous optimization in ZWMath →

Review the concept: Convergence with Lipschitz gradient

Result guaranteeing that gradient descent with a suitable step size converges for differentiable functions whose gradient \( \nabla f \) is Lipschitz continuous with constant \( L \).

\[f(x_k)-f^* \le \frac{L\|x_0-x^*\|^2}{2k}\]

More practice problems: convergence with lipschitz gradient

← ZW-CONVERGENCE-WITH-LIPSCHITZ-GRADIENT-005 ZW-CONVERGENCE-WITH-LIPSCHITZ-GRADIENT-007 →