Exercise · ZW-CONVERGENCE-WITH-LIPSCHITZ-GRADIENT-004 · ★☆☆ Basic

Which inequality follows from the Lipschitz condition on the gradient?

Choose one option.

Show answer
  • B. \( f(y)\le f(x)+\nabla f(x)^T(y-x)+\frac{L}{2}\|y-x\|^2 \)

Explanation

This is the form of the descent lemma derived from the Lipschitz condition. The option with the reversed inequality and no quadratic term does not follow from the hypothesis.

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Review the concept: Convergence with Lipschitz gradient

Result guaranteeing that gradient descent with a suitable step size converges for differentiable functions whose gradient \( \nabla f \) is Lipschitz continuous with constant \( L \).

\[f(x_k)-f^* \le \frac{L\|x_0-x^*\|^2}{2k}\]

More practice problems: convergence with lipschitz gradient

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