Exercise · ZW-CRAMERS-RULE-010 · ★★★ Advanced
Let \(A\) be a square matrix with integer entries and \(\det A=1\), and \(\mathbf{b}\) a vector with integer entries. What can be said about the solution of \(A\mathbf{x}=\mathbf{b}\)?
Choose one option.
A At least one component is not an integer B All its components are integers C It can be any rational number, with no further information D It does not exist, since \(\det A\) must differ from \(1\)
Show answer B. All its components are integers
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Explanation By Cramer's rule , \(x_i=\det A_i/1=\det A_i\), and the determinant of an integer matrix is an integer. Hence every \(x_i\) is an integer.
Cramer's rule gives the unique solution of a square system, whose coefficient matrix \(A\) has nonzero determinant , as a quotient of determinants.
\[x_i=\frac{\det A_i}{\det A}\]
More practice problems: cramer's rule