Exercise · ZW-CRITICAL-POINTS-008 · ★★★ Advanced

How many critical points does \(f(x)=x^{2/3}\) have, and which are they?

Choose one option.

Show answer
  • A. One: \(x=0\), where \(f'\) does not exist

Explanation

For \(x\neq 0\), \(f'(x)=\frac{2}{3}x^{-1/3}\) is never zero. At \(x=0\) the derivative does not exist, so it is the only critical point.

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Review the concept: Critical points

A critical point of \(f\) is a number \(c\) in the domain where \(f^{\prime}(c)=0\) or \(f^{\prime}(c)\) does not exist. Local maxima and minima of a function at an interior point occur at critical points.

\[f'(c)=0\ \ \text{or}\ \ f'(c)\ \text{does not exist}\]

More practice problems: critical points

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