Exercise · ZW-DIAGONALIZATION-008 · ★★☆ Intermediate

Let \(\begin{pmatrix}1&1&0\\0&1&0\\0&0&2\end{pmatrix}\), with eigenvalues 1 (double) and 2. Is it diagonalizable?

Choose one option.

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  • A. No: \(\dim E_1=1\) but 1 is a double root

Explanation

To diagonalize, \(\dim E_1\) must equal the multiplicity 2, but it is 1. A repeated eigenvalue does not prevent diagonalizing if its eigenspace is large enough.

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Review the concept: Diagonalization

A square matrix \(A\) is diagonalizable if it is similar to a diagonal matrix \(D\), that is, if it can be written as an invertible matrix \(P\) times \(D\) times the inverse of \(P\).

\[A=PDP^{-1}\]

More practice problems: diagonalization

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