Exercise · ZW-DIAGONALIZATION-009 · ★★★ Advanced

A \(3\times 3\) matrix has eigenvalues 2 (double) and 5 (simple). Which condition is equivalent to being diagonalizable?

Choose one option.

Show answer
  • C. \(\dim E_2=2\)

Explanation

\(\dim E_5=1\) always holds, and invertible is not enough. What is needed is that \(E_2\) has dimension 2 to complete three independent eigenvectors.

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Review the concept: Diagonalization

A square matrix \(A\) is diagonalizable if it is similar to a diagonal matrix \(D\), that is, if it can be written as an invertible matrix \(P\) times \(D\) times the inverse of \(P\).

\[A=PDP^{-1}\]

More practice problems: diagonalization

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