Exercise · ZW-EIGENSPACE-006 · ★★☆ Intermediate
Let \(\begin{pmatrix}1&2\\2&4\end{pmatrix}\). A nonzero vector lies in the eigenspace of \(\lambda=0\) if and only if it is a multiple of:
Choose one option.
Show answer
- D. \((2,-1)\)
Explanation
Solve \(Bv=0\): \(x+2y=0\), so \(v=(2,-1)\). The vector \((1,2)\) is an eigenvector for \(\lambda=5\).
Review the concept: Eigenspace
The eigenspace \(E_\lambda\) of a square matrix \(A\) for the eigenvalue \(\lambda\) is zero together with the eigenvectors of \(\lambda\), where \(I\) is the identity of the size of \(A\).
\[E_\lambda=\ker(A-\lambda I)\]
More practice problems: eigenspace
- ZW-EIGENSPACE-001 Let [4 1; 2 3]. Which vector spans the eigenspace of λ=5?
- ZW-EIGENSPACE-002 Let A=diag(2,2,3). What is the dimension of the eigenspace of λ=2?
- ZW-EIGENSPACE-003 Let A=3I of size 2× 2. What is the eigenspace of λ=3?
- ZW-EIGENSPACE-004 Let [2 1; 0 2]. What is the dimension of the eigenspace of λ=2?
- ZW-EIGENSPACE-005 Which statement about the eigenspace E_λ is true?
- ZW-EIGENSPACE-007 Let [1 1 0; 0 1 0; 0 0 2]. What is the dimension of the eigenspace of λ=1?
- ZW-EIGENSPACE-008 Let A=diag(1,2) and v=(1,1), the sum of an eigenvector for λ=1 and one for λ=2. Is v an eigenvector…
- ZW-EIGENSPACE-009 The characteristic polynomial of a 3× 3 matrix is (λ-2)^2(λ-5). What is the dimension of the eigens…