Exercise · ZW-EIGENSPACE-001 · ★☆☆ Basic

Let \(\begin{pmatrix}4&1\\2&3\end{pmatrix}\). Which vector spans the eigenspace of \(\lambda=5\)?

Choose one option.

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  • C. \((1,1)\)

Explanation

\((A-5I)v=0\) reduces to \(-x+y=0\), so \(v=(1,1)\). The vector \((1,-2)\) belongs to the eigenspace of \(\lambda=2\), not of 5.

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Review the concept: Eigenspace

The eigenspace \(E_\lambda\) of a square matrix \(A\) for the eigenvalue \(\lambda\) is zero together with the eigenvectors of \(\lambda\), where \(I\) is the identity of the size of \(A\).

\[E_\lambda=\ker(A-\lambda I)\]

More practice problems: eigenspace

ZW-EIGENSPACE-002 →