Exercise · ZW-HARMONIC-FUNCTION-009 · ★★★ Advanced

The function \(u=\ln(x^2+y^2)\) is harmonic on \(\mathbb{C}\setminus\{0\}\). Does it have a harmonic conjugate on that whole domain?

Choose one option.

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  • B. No: the conjugate would be \(2\arg z\), which is not single-valued around the origin

Explanation

\(u=2\ln|z|=\operatorname{Re}(2\log z)\), whose local conjugate is \(2\arg z\); going once around \(0\) it changes by \(4\pi\). The domain is not simply connected.

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Review the concept: Harmonic function

A real function \(u\) of two variables, with continuous second partial derivatives on an open set \(U\) of the plane, is harmonic if its Laplacian \(\Delta u\) is zero throughout \(U\).

\[\Delta u=\frac{\partial^2 u}{\partial x^2}+\frac{\partial^2 u}{\partial y^2}=0\]

More practice problems: harmonic function

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