Exercise · ZW-INITIAL-VALUE-PROBLEM-006 · ★★☆ Intermediate
If \(y'=3x^2\) and \(y(1)=2\), what is \(y(2)\)?
Choose one option.
Show answer
- C. 9
Exercise · ZW-INITIAL-VALUE-PROBLEM-006 · ★★☆ Intermediate
Choose one option.
Integrating, \(y=x^3+C\); \(2=1+C\) gives \(C=1\), so \(y(2)=8+1=9\).
An initial value problem asks for the solution of a differential equation that, in addition, takes given values at a given point.
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