Exercise · ZW-INTERMEDIATE-VALUE-THEOREM-020 · ★★★ Advanced
How many real roots does \(f(x)=x^3-3x\) have on \([-2,2]\), where \(f(-2)=-2\) and \(f(2)=2\)?
Choose one option.
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- A. \(3\)
Exercise · ZW-INTERMEDIATE-VALUE-THEOREM-020 · ★★★ Advanced
Choose one option.
\(x^3-3x=x(x^2-3)=0\) gives \(x=0,\pm\sqrt3\), and all three lie in \([-2,2]\). The theorem only ensures at least one.
If \(f\) is continuous on \([a,b]\) and \(N\) lies between \(f(a)\) and \(f(b)\), there is some \(c\in(a,b)\) with \(f(c)=N\).