Exercise · ZW-LIMIT-OF-A-FUNCTION-011 · ★☆☆ Basic
For \(f(x)=3x+1\), with limit \(7\) at \(x=2\) and \(\varepsilon=0.3\), what is the largest \(\delta\) that works?
Choose one option.
Show answer
- C. \(\delta=0.1\)
Exercise · ZW-LIMIT-OF-A-FUNCTION-011 · ★☆☆ Basic
Choose one option.
\(|f(x)-7|=3|x-2|<0.3\) is equivalent to \(|x-2|<0.1\). With \(\delta=0.3\) an \(x\) like \(2.2\) would give \(|f(x)-7|=0.6\).
The limit of \(f\) as \(x\) approaches \(a\) is \(L\) if \(f(x)\) gets as close to \(L\) as we like when \(x\) is taken sufficiently close to \(a\), regardless of what happens at \(x=a\).