Exercise · ZW-LIMIT-OF-A-FUNCTION-016 · ★★☆ Intermediate

If \(\lim_{x\to2}(x^2+1)=5\) and \(x_n=2+\frac1n\), what does \(f(x_n)=x_n^2+1\) converge to?

Choose one option.

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  • B. \(5\)

Explanation

Since \(x_n\to2\) with \(x_n\ne2\), the sequential criterion gives \(f(x_n)\to5\). Directly: \((2+\frac1n)^2+1\to4+1=5\).

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Review the concept: Limit of a function

The limit of \(f\) as \(x\) approaches \(a\) is \(L\) if \(f(x)\) gets as close to \(L\) as we like when \(x\) is taken sufficiently close to \(a\), regardless of what happens at \(x=a\).

\[\lim_{x\to a} f(x)=L\]

More practice problems: limit of a function

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