Exercise · ZW-LIMIT-OF-A-FUNCTION-016 · ★★☆ Intermediate
If \(\lim_{x\to2}(x^2+1)=5\) and \(x_n=2+\frac1n\), what does \(f(x_n)=x_n^2+1\) converge to?
Choose one option.
Show answer
- B. \(5\)
Exercise · ZW-LIMIT-OF-A-FUNCTION-016 · ★★☆ Intermediate
Choose one option.
Since \(x_n\to2\) with \(x_n\ne2\), the sequential criterion gives \(f(x_n)\to5\). Directly: \((2+\frac1n)^2+1\to4+1=5\).
The limit of \(f\) as \(x\) approaches \(a\) is \(L\) if \(f(x)\) gets as close to \(L\) as we like when \(x\) is taken sufficiently close to \(a\), regardless of what happens at \(x=a\).