Exercise · ZW-LIMITS-AT-INFINITY-005 · ★★☆ Intermediate

Compute \(\lim_{x\to\infty}\,\frac{\sqrt{x^{2} + 1}}{x}\).

Choose one option.

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  • A. \(1\)

Explanation

For large positive x, \(\sqrt{x^{2}+1}\approx x\), so the quotient approaches 1. Formally, \(\dfrac{\sqrt{x^{2}+1}}{x}=\sqrt{1+\dfrac{1}{x^{2}}}\to1\).

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Review the concept: Limits at infinity

The limit of \(f\) as \(x\) tends to infinity describes what happens to \(f(x)\) when \(x\) grows without bound. For a quotient of polynomials, the result is decided by the quotient of the highest-degree terms.

\[\lim_{x\to\infty}\frac{a_n x^{n}+\cdots}{b_n x^{n}+\cdots}=\frac{a_n}{b_n}\]

More practice problems: limits at infinity

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