Exercise · ZW-LOCAL-MAXIMA-AND-MINIMA-008 · ★★★ Advanced

Is it true that if \(f'(c)=0\), then \(c\) is a local extremum of \(f\)?

Choose one option.

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  • B. No: for \(f(x)=x^{3}\) at \(c=0\), \(f'(0)=0\) but there is no extremum

Explanation

It is false: \(f'(x)=3x^{2}\geq 0\) does not change sign at \(0\), so \(f\) is increasing and \(x=0\) is not an extremum. Setting \(f'=0\) is necessary but not sufficient.

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Review the concept: Local maxima and minima

A local maximum of \(f\) at \(c\) is a value \(f(c)\) greater than or equal to the values of \(f\) on some neighborhood of \(c\); a local minimum, less than or equal.

\[f'(c)=0,\ f''(c)>0\ \Rightarrow\ \text{local minimum}\]

More practice problems: local maxima and minima

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