Exercise · ZW-MEAN-VALUE-THEOREM-007 · ★★☆ Intermediate

Find the value c guaranteed by the mean value theorem for \(f(x)=x^{2}-4x\) on \([0,4]\).

Choose one option.

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  • B. \(2\)

Explanation

Since \(f(0)=f(4)=0\), the secant has slope \(0\). We solve \(f'(c)=2c-4=0\) and get \(c=2\), inside \((0,4)\).

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Review the concept: Mean value theorem

If \(f\) is continuous on \([a,b]\) and differentiable on \((a,b)\), there is a \(c\in(a,b)\) such that the slope of the tangent at \(c\) equals the slope of the secant line joining \((a,f(a))\) and \((b,f(b))\).

\[f'(c)=\frac{f(b)-f(a)}{b-a}\]

More practice problems: mean value theorem

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