Exercise · ZW-MINKOWSKI-INEQUALITY-006 · ★★☆ Intermediate

With \(f(x)=x\) on \([0,1]\) and \(p=2\), what is \(\|f\|_2\)?

Choose one option.

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  • D. \(1/\sqrt{3}\)

Explanation

Since \(\int_0^1 x^2\,dx=1/3\), the norm is the square root of that value. Forgetting the square root gives \(1/3\), and confusing the norm with the integral of \(x\) gives \(1/2\).

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Review the concept: Minkowski inequality

Inequality stating that the \(L^p\) norm of a sum of functions is at most the sum of their \(L^p\) norms, for \(p \ge 1\).

\[\|f+g\|_p \le \|f\|_p + \|g\|_p\]

More practice problems: minkowski inequality

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