Exercise · ZW-MULTIPLICATIVE-ARITHMETIC-FUNCTION-007 · ★★☆ Intermediate
Compute \(\tau(2^{4}\cdot 5^{2})\).
Choose one option.
Show answer
- D. 15
Explanation
By multiplicativity, \(\tau=(4+1)(2+1)=15\). The option of 30 is double the correct result.
Review the concept: Multiplicative arithmetic function
An arithmetic function \(f\) is multiplicative if \(f(1)=1\) and \(f(mn)=f(m)f(n)\) whenever \(\gcd(m,n)=1\). Its behavior is determined by its values on prime powers.
\[f(mn)=f(m)f(n)\text{ if }\gcd(m,n)=1\]
More practice problems: multiplicative arithmetic function
- ZW-MULTIPLICATIVE-ARITHMETIC-FUNCTION-001 What is the value of τ(12)?
- ZW-MULTIPLICATIVE-ARITHMETIC-FUNCTION-002 If f is multiplicative and gcd(m,n)=1, which expression equals f(mn)?
- ZW-MULTIPLICATIVE-ARITHMETIC-FUNCTION-003 What is the value of τ(p^3) for a prime p?
- ZW-MULTIPLICATIVE-ARITHMETIC-FUNCTION-004 Which of these functions is not multiplicative?
- ZW-MULTIPLICATIVE-ARITHMETIC-FUNCTION-005 If f is multiplicative, what is f(1)?
- ZW-MULTIPLICATIVE-ARITHMETIC-FUNCTION-006 If τ(n)=12 and n=2^2· 3^?, what is the exponent of 3?
- ZW-MULTIPLICATIVE-ARITHMETIC-FUNCTION-008 If f is multiplicative with f(2)=3 and f(5)=4, what is f(10)?
- ZW-MULTIPLICATIVE-ARITHMETIC-FUNCTION-009 When computing τ(4) as τ(2)·τ(2), why does the multiplicativity rule not apply?
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