Exercise · ZW-MULTIVARIABLE-LIMIT-009 · ★★★ Advanced
For \(f(x,y)=\dfrac{xy^2}{x^2+y^4}\), the limit at \((0,0)\):
Choose one option.
A Equals \(0\), since it is \(0\) along every line \(y=mx\) B Equals \(\dfrac12\) C Equals \(1\) D Does not exist: it is \(0\) along lines and \(\dfrac12\) along \(x=y^2\)
Show answer D. Does not exist: it is \(0\) along lines and \(\dfrac12\) along \(x=y^2\)
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Explanation Along \(y=mx\) it tends to \(0\), but along the parabola \(x=y^2\) it equals \(\dfrac{y^4}{2y^4}=\dfrac12\). Testing only lines is misleading.
The limit of a function \(f\) at a point \(\mathbf a\) is the number \(L\) that the values \(f(\mathbf x)\) approach as \(\mathbf x\) gets close to \(\mathbf a\) along any path.
\[\lim_{\mathbf x\to\mathbf a} f(\mathbf x)=L\]
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