Exercise · ZW-MULTIVARIABLE-LIMIT-010 · ★★★ Advanced
Compute \(\displaystyle\lim_{(x,y)\to(0,0)}(x^2+y^2)\ln(x^2+y^2)\).
Choose one option.
A \(0\) B \(-\infty\) C \(1\) D Does not exist
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Explanation With \(r^2=x^2+y^2\) we get \(r^2\ln r^2\to0\) as \(r\to0^+\), since the power beats the logarithm.
The limit of a function \(f\) at a point \(\mathbf a\) is the number \(L\) that the values \(f(\mathbf x)\) approach as \(\mathbf x\) gets close to \(\mathbf a\) along any path.
\[\lim_{\mathbf x\to\mathbf a} f(\mathbf x)=L\]
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