Exercise · ZW-NEWTON-DIVIDED-DIFFERENCES-009 · ★★★ Advanced

For \(f(x)=x^3\) with nodes \(0,1,2,3\), what is \(f[x_0,x_1,x_2,x_3]\)?

Choose one option.

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  • B. \(1\)

Explanation

With \(f[0,1]=1\), \(f[1,2]=7\) and \(f[2,3]=19\), you get \(f[0,1,2]=3\) and \(f[1,2,3]=6\), so \(\frac{6-3}{3-0}=1\).

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Review the concept: Newton divided differences

Newton divided differences are recursive quotients of function values at nodes that serve as the coefficients of the interpolating polynomial in Newton form.

\[f[x_i..x_{i+k}]=\frac{f[x_{i+1}..x_{i+k}]-f[x_i..x_{i+k-1}]}{x_{i+k}-x_i}\]

More practice problems: newton divided differences

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