Exercise · ZW-OPEN-COVER-010 · ★★★ Advanced
\(\mathcal{U}\) covers \(A\) and \(\mathcal{V}\) covers \(B\). Which statement is always true?
Choose one option.
A \(\mathcal{U}\cap\mathcal{V}\) covers \(A\cap B\). B \(\mathcal{U}\) covers \(A\cup B\). C \(\mathcal{U}\cup\mathcal{V}\) covers \(A\cup B\). D \(\mathcal{U}\cup\mathcal{V}\) covers \(A\cap B\) but not \(A\cup B\).
Show answer C. \(\mathcal{U}\cup\mathcal{V}\) covers \(A\cup B\).
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Explanation Every point of \(A\cup B\) lies in \(A\) or in \(B\), hence in some member of \(\mathcal{U}\) or \(\mathcal{V}\). The claim about \(\mathcal{U}\cap\mathcal{V}\) fails, for instance, when \(\mathcal{U}\cap\mathcal{V}=\varnothing\) but \(A\cap B\ne\varnothing\).
An open cover of a subset \(A\) of a topological space \(X\) is a family \(\mathcal{U}\) of open sets \(U\) of \(X\) whose union contains \(A\).
\[A\subseteq\bigcup_{U\in\mathcal{U}}U\]
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